$$ \int_a^b f(x) dx = f(x_1)(b - a) + \frac{f''(\xi)}{24} (b - a)^3. $$ где $x_1 = (a + b) / 2$ и $\xi \in (a; b)$.
$$ \int_a^b f(x) dx = \frac{h}{2}\left[f(x_1) + f(x_2)\right] - \frac{h^3}{12} f^{\prime\prime}(\xi), $$ где $x_1 = a$, $x_2 = b$, $h = b - a$ и $\xi \in (a; b)$.
$$ \int_a^b f(x) dx = \frac{h}{3}\left[f(x_1) + 4 f(x_2) + f(x_3)\right] - \frac{h^5}{90} f^{(4)}(\xi), $$ где $x_1 = a$, $x_2 = x_1 + h$, $x_3 = x_1 + 2h = b$ и $\xi \in (a; b)$.